Kepler-58 e
Kepler-58 e is a super-Earth orbiting Kepler-58 in the constellation Cygnus. It lies about 3,161 light-years from Earth and was discovered in 2023 using the transit method.
How Big Is Kepler-58 e?
Kepler-58 e has a radius of 1.61 times that of Earth.
Is Kepler-58 e in the Habitable Zone?
Kepler-58 e orbits inside the inner edge of the habitable zone of Kepler-58. So close to its star, surface conditions are far too hot for liquid water.
Habitable zone of Kepler-58: 0.787–1.852 AU (conservative: 0.997–1.756 AU), per Kopparapu et al. (2014). Earth orbits the Sun at 1 AU.
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Temperature on Kepler-58 e
The equilibrium temperature of Kepler-58 e is about 1,212 K (939 °C) — hot enough to melt many metals. This estimate ignores any atmosphere, which could change surface temperatures dramatically — Earth's greenhouse effect adds about 33 °C. It receives 512 times the stellar energy that Earth gets from the Sun.
Orbit and Year Length
A year on Kepler-58 e — one full orbit around Kepler-58 — lasts 4.46 Earth days, shorter than Mercury's 88-day year. It orbits at an average distance of 0.053 AU — closer to its star than Mercury is to the Sun.
How Was Kepler-58 e Discovered?
Kepler-58 e was discovered in 2023 using the transit method, with observations from Kepler.
The transit method watches a star for the tiny, regular dip in brightness that occurs when a planet crosses in front of it. The depth and timing of these dips reveal the planet's size and orbital period.
How Far Away Is Kepler-58 e?
Kepler-58 e is 3,161.3 light-years (969.3 parsecs) from Earth. Light arriving here tonight left the planet about 3,161 years ago. A probe traveling at the speed of Voyager 1 — about 17 km/s, the fastest outbound spacecraft ever launched — would need roughly 55,638,880 years to make the journey.
Earth Similarity Index
The Earth Similarity Index (ESI) scores how physically similar a planet is to Earth, from 0 to 1, based on radius, density, escape velocity and surface temperature. Kepler-58 e scores 0.28, ranking #2,329 of 5,568 planets with a known ESI. For reference, Mars scores about 0.70.
The Host Star: Kepler-58
Kepler-58
- Surface temperature
- 5,843 K (Sun: 5,772 K)
- Mass
- 0.95 M☉
- Radius
- 1.03 R☉
The Kepler-58 Planetary System
Kepler-58 e is one of 4 known planets in the Kepler-58 system. Its siblings:
- Kepler-58 b (Super Earth)
- Kepler-58 c (Super Earth)
- Kepler-58 d (Mini Neptune)
Kepler-58 e — Complete Data
| Radius | 1.610 Earth radii (0.144 Jupiter radii) |
|---|---|
| Orbital period | 4.46 days |
| Orbital distance | 0.053 AU |
| Equilibrium temperature | 1,212 K (939 °C) |
| Stellar irradiation | 511.60× Earth |
| Earth Similarity Index | 0.28 |
| Distance from Earth | 3,161.3 light-years (969.3 parsecs) |
| Constellation | Cygnus |
| Discovery method | Transit |
| Discovery facility | Kepler |
| Discovery year | 2023 |
Data: NASA Exoplanet Archive, last updated 2017-05-08. Earth Similarity Index: PHL @ UPR Arecibo.
Frequently Asked Questions About Kepler-58 e
Is Kepler-58 e habitable?
No — Kepler-58 e orbits too close to its star and is too hot for liquid water to exist on its surface.
How far away is Kepler-58 e?
Kepler-58 e is about 3,161 light-years from Earth in the constellation Cygnus. A spacecraft traveling as fast as Voyager 1 (about 17 km/s) would need roughly 55,638,880 years to get there.
How big is Kepler-58 e compared to Earth?
Kepler-58 e has 1.61 times the radius of Earth.
How long is a year on Kepler-58 e?
One orbit around Kepler-58 takes 4.5 Earth days — short enough that 82 of its years would fit into one Earth year.
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